Question

Вероятность попадания по цели при одном выстреле у первого орудия равна 0.6, у второго - 0,7. Найти вероятность того, что по цели попадет хотя бы одно орудие после того, как оба сделают по одному выстрелу

Answer 1

Вероятность второго попадания у 1 орудия=0.6^2=0.36
Вероятность второго попадания у 2 орудия=0.7^2=0.49
Вероятность попадания хотя бы 1 орудия=сумме 2 вероятностей
0.49+0.36=0.85
Ответ:0.85

Answer 2

Problem Analysis

We are given the probability of hitting the target with the first weapon as 0.6 and with the second weapon as 0.7. We need to find the probability that at least one weapon hits the target after both weapons have fired one shot each.

Solution

To find the probability that at least one weapon hits the target, we can use the complement rule. The complement of "at least one weapon hits the target" is "neither weapon hits the target." Therefore, we can find the probability of neither weapon hitting the target and subtract it from 1 to get the desired probability.

Let's calculate the probability of neither weapon hitting the target: - The probability of the first weapon not hitting the target is 1 - 0.6 = 0.4. - The probability of the second weapon not hitting the target is 1 - 0.7 = 0.3.

Using the multiplication rule for independent events, we can calculate the probability of neither weapon hitting the target after both weapons have fired one shot each: P(neither weapon hits the target) = 0.4 * 0.3 = 0.12.

Now, we can find the probability that at least one weapon hits the target: P(at least one weapon hits the target) = 1 - P(neither weapon hits the target) = 1 - 0.12 = 0.88.

Therefore, the probability that at least one weapon hits the target after both weapons have fired one shot each is 0.88.

Answer

The probability that at least one weapon hits the target after both weapons have fired one shot each is 0.88.