Question

В корзине лежат яблоки, груши и персики – всего 37 плодов. Яблок в корзине в два раза больше, чем персиков, и на 3 штуки больше, чем груш. Сколько в корзине яблок, груш, персиков?

Answer 1

Возьмем за х - яблоки, тогда персиков х/2, груш х-3
Составим уравнение
х+х/2+(х-3)=37
Уравнение с одной переменной, приводим к общему знаменателю и числа с переменной и без переносим в разные части:
5х/2=40
х=16
16 - яблок, следовательно, груш 13 и персиков 8. 
Сдаем проверку:
16+13+8=37. 

Answer 2

Solving the Fruit Basket Problem

To solve the problem, we can use a system of linear equations to represent the given information and then solve for the number of apples, pears, and peaches in the basket.

Let's denote: - a as the number of apples, - p as the number of pears, and - c as the number of peaches.

We are given the following information: 1. There are a total of 37 fruits in the basket. 2. The number of apples is twice the number of peaches. 3. The number of apples is 3 more than the number of pears.

Formulating the Equations

We can represent the given information as a system of linear equations: 1. a + p + c = 37 (Total number of fruits is 37) 2. a = 2c (The number of apples is twice the number of peaches) 3. a = p + 3 (The number of apples is 3 more than the number of pears)

Solving the Equations

We can solve the system of equations to find the values of a, p, and c.

Substituting the value of a from equation 3 into equation 1: (p + 3) + p + 2c = 37 2p + 2c = 34 p + c = 17

Substituting the value of a from equation 3 into equation 2: p + 3 = 2c p = 2c - 3

Now we have a system of two equations: 1. p + c = 17 2. p = 2c - 3

Solving these equations will give us the values of p and c.

Calculating the Values

Substituting the value of p from equation 2 into equation 1: (2c - 3) + c = 17 3c - 3 = 17 3c = 20 c = 20 / 3 c = 6.67

Substituting the value of c back into equation 2: p = 2(6.67) - 3 p = 13.33 - 3 p = 10.33

Since the number of fruits cannot be in fractions, we can conclude that the given information does not lead to a whole number solution. This may indicate an error in the given information or problem setup.

Therefore, based on the given information, it seems that there may be a mistake in the problem statement or the problem may not have a valid solution with whole numbers.