Question

Скажите пожалуйста ответ на задачу: три пятиклассника купили 14 пирожков, причём Коля купил в 2 раза меньше, чем Вася, а Женя - больше Коли, но меньше Васи. Сколько пирожков купил каждый

Answer 1

Коля-3 пирожка
Вася- пирожков
Женя- 5 пирожков

Answer 2

Task:

Три пятиклассника купили 14 пирожков, причём Коля купил в 2 раза меньше, чем Вася, а Женя - больше Коли, но меньше Васи. Сколько пирожков купил каждый?

Answer:

Let's solve this problem step by step.

Let's assume that the number of pies Kolya bought is x. According to the problem, Vasya bought twice as many pies as Kolya, so Vasya bought 2x pies. And Zhena bought more pies than Kolya but less than Vasya, so Zhena bought y pies, where y > x and y < 2x.

The total number of pies bought by the three students is 14, so we can write the equation:

x + 2x + y = 14

Simplifying the equation, we get:

3x + y = 14

To find the values of x and y, we need another equation. However, the problem does not provide any additional information. Therefore, we cannot determine the exact values of x and y.

However, we can find possible solutions by substituting different values for x and solving for y. Let's try some values:

- If we assume that Kolya bought 1 pie (x = 1), then Vasya bought 2 pies (2x = 2), and the equation becomes:

3(1) + y = 14 3 + y = 14 y = 14 - 3 y = 11 So, Kolya bought 1 pie, Vasya bought 2 pies, and Zhena bought 11 pies.

- If we assume that Kolya bought 2 pies (x = 2), then Vasya bought 4 pies (2x = 4), and the equation becomes:

3(2) + y = 14 6 + y = 14 y = 14 - 6 y = 8 So, Kolya bought 2 pies, Vasya bought 4 pies, and Zhena bought 8 pies.

- We can continue this process and try different values for x to find other possible solutions.

In conclusion, based on the given information, there are multiple possible solutions for the number of pies each student bought. Some possible solutions are:

- Kolya: 1 pie, Vasya: 2 pies, Zhena: 11 pies. - Kolya: 2 pies, Vasya: 4 pies, Zhena: 8 pies.

Please note that these are just examples, and there may be other valid solutions as well.

I hope this helps! Let me know if you have any further questions.