Question

В 1713 году на трёх склад ах демидовских заводов в москве лежало 500 000 ручных гранат.на первом и втором складах вместе -было 289 000 гранат.сколько гранат лежало на каждом складе,если на втором складе гранат было на 30 000 больше,чем на третьем

Answer 1

1)500000-289000=211000 гранат-на третьем складе.

2)211000+30000=241000 гранат-на втором складе.

3)289000-241000=48000 гранат-на первом складе.

Answer 2

Calculating the Number of Grenades on Each Warehouse in 1713

To solve this problem, we can use algebra to represent the given information and then solve for the number of grenades on each warehouse.

Let's denote: - The number of grenades on the first warehouse as x - The number of grenades on the second warehouse as y - The number of grenades on the third warehouse as z

We are given the following information: 1. The total number of grenades on the first and second warehouses is 289,000. 2. The number of grenades on the second warehouse is 30,000 more than the number on the third warehouse. 3. The total number of grenades on all three warehouses is 500,000.

Using this information, we can set up the following equations: - x + y = 289,000 (Equation 1) - y = z + 30,000 (Equation 2) - x + y + z = 500,000 (Equation 3)

We can solve this system of equations to find the values of x, y, and z.

Solving the Equations

Substitute the value of y from Equation 2 into Equation 1: - x + (z + 30,000) = 289,000 - x + z + 30,000 = 289,000 - x + z = 259,000 (Equation 4)

Now, substitute the values of x and y from Equations 1 and 2 into Equation 3: - (x) + (z + 30,000) + z = 500,000 - x + 2z + 30,000 = 500,000 - x + 2z = 470,000 (Equation 5)

We now have a system of two equations (Equations 4 and 5) with two variables (x and z). We can solve this system to find the values of x and z.

Calculating the Number of Grenades on Each Warehouse

Using the system of equations: - x + z = 259,000 (Equation 4) - x + 2z = 470,000 (Equation 5)

Subtract Equation 4 from Equation 5: - (x + 2z) - (x + z) = 470,000 - 259,000 - x + 2z - x - z = 211,000 - z = 211,000

Now that we have the value of z, we can substitute it back into Equation 4 to find x: - x + 211,000 = 259,000 - x = 259,000 - 211,000 - x = 48,000

So, the number of grenades on each warehouse is: - First warehouse (x): 48,000 grenades - Second warehouse (y): 211,000 grenades - Third warehouse (z): 211,000 grenades

Therefore, based on the given information, there were 48,000 grenades on the first warehouse, and 211,000 grenades on both the second and third warehouses in 1713.