Question

Пол читательного зала библиотеки имеет размеры 22целых 2/5м умножить 15целых1/2м а высота 5м определите сколько мест может быть в этой бибилиотеке учитывая что по нормам на 1 читателя должно мыть 4м в кубе воздуха

Answer 1

1. 22 2/5 * 15 1/2 = 112/5 * 31/2=1736/5 кв.м площадь библиотеки

2. 1736/5 *5 = 1736 куб.м объем библиотеки

3. 1736 : 4 = 434 места может быть в бибилиотеке

Answer 2

Calculating the Capacity of the Library

To determine the number of seats the library can accommodate, we can calculate the volume of the reading hall and then divide it by the required volume per reader.

The volume of the reading hall can be calculated using the formula: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \]

Given: - Length = 22 2/5 m - Width = 15 1/2 m - Height = 5 m

Let's calculate the volume of the reading hall.

Calculating the Volume of the Reading Hall

The volume of the reading hall can be calculated as follows: \[ \text{Volume} = 22 \frac{2}{5} \, \text{m} \times 15 \frac{1}{2} \, \text{m} \times 5 \, \text{m} \]

\[ \text{Volume} = \left(22 \frac{2}{5} \times 15 \frac{1}{2} \times 5\right) \, \text{m}^3 \]

\[ \text{Volume} = \left(\frac{112}{5} \times \frac{31}{2} \times 5\right) \, \text{m}^3 \]

\[ \text{Volume} = \left(\frac{112 \times 31}{5 \times 2} \times 5\right) \, \text{m}^3 \]

\[ \text{Volume} = \left(\frac{3472}{10} \times 5\right) \, \text{m}^3 \]

\[ \text{Volume} = 1736 \, \text{m}^3 \]

So, the volume of the reading hall is 1736 cubic meters.

Calculating the Number of Seats

Now, we need to calculate the number of seats the library can accommodate based on the required volume per reader.

Given: - Volume per reader = 4 cubic meters

The number of seats can be calculated using the formula: \[ \text{Number of seats} = \frac{\text{Volume of the reading hall}}{\text{Volume per reader}} \]

\[ \text{Number of seats} = \frac{1736 \, \text{m}^3}{4 \, \text{m}^3} \]

\[ \text{Number of seats} = 434 \]

So, the library can accommodate 434 readers based on the requirement of 4 cubic meters of air per reader.