Question

Из двух городов,расстояние между которым960 км, навстречу друг другу в 8 ч утра вышли два поезда. они встретились в 6ч вечера того же дня.Найди скорость первого поезда,если скорость второго-40км/ч Решите пожалуйста с условием!!

Answer 1

4+6=10 часов были в пути
40x10=400 км прошёл первый поезд
960-400=560 км прошёл второй поезд
560:10=56 км в час скорость второго поезда

Answer 2

Problem Analysis

We are given that two trains start from two cities that are 960 km apart and are heading towards each other. The first train has an unknown speed, and the second train has a speed of 40 km/h. The trains meet at 6:00 PM on the same day they started, and they started at 8:00 AM. We need to find the speed of the first train.

Solution

To solve this problem, we can use the formula: Distance = Speed x Time.

Let's assume the speed of the first train is x km/h.

The first train travels for 10 hours (from 8:00 AM to 6:00 PM), and the second train also travels for 10 hours.

Using the formula, we can set up the following equation:

Distance covered by the first train + Distance covered by the second train = Total distance between the cities

x km/h * 10 hours + 40 km/h * 10 hours = 960 km

Simplifying the equation:

10x + 400 = 960

10x = 960 - 400

10x = 560

x = 560 / 10

x = 56

Therefore, the speed of the first train is 56 km/h.

Answer

The speed of the first train is 56 km/h.