Question

СРОЧНО : ИЗ ДВУХ ПУНКТОВ РАССТАЯНИЕ МЕЖДУ КОТОРЫМИ 210 КМ НА ВСТРЕЧЮ ДРУК ДРУГУ ОДНАВРЕМЕННО ВЫШЛИ ДВА ЭЛЕКТРО ПОИЗДА . СКОРОСТЬ ОДНОГО НА 5КМ/Ч БОЛЬШЕ СКОРОСТИ ДРУГОГО. НАЙДИТЕ СКОРОСТЬ КАЖДОГО ЭЛЕКТРО ПОИЗДА ЕСЛИ ОНИ ВСТРЕТИЛИСЬ ЧЕРЕЗ 2 Ч ПОСЛЕ СВОЕГО ВЫХОДА!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! ССССССРРРРРРРРРООООООООЧЧЧЧЧЧЧЧЧЧНННННННООООООООО!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Х(км/ч) - скорость 1-ого поезда
х+5(км/ч) скорость 2 поезда
1) 210 :2=105 (км/ч) скорость сближения поездов
2) х+х+5=105
2х =100
х=50(км/ч) скорость первого поезда
50+5=55(км/ч) скорость 2 поезда

Answer 2

Train Speed Problem

To solve this problem, we can use the concept of relative speed. When two objects are moving towards each other, their relative speed is the sum of their individual speeds. We can use this concept to find the speeds of the two trains.

Let's denote: - Speed of the slower train as x km/h - Speed of the faster train as (x + 5) km/h

The relative speed of the two trains when they meet is 210 km/h, and they meet after 2 hours.

Using the formula: Distance = Speed × Time, we can set up the equation:

Distance = (Speed of train 1 + Speed of train 2) × Time

Calculations

The distance covered by the first train in 2 hours is 2x km, and the distance covered by the second train in 2 hours is 2(x + 5) km.

According to the problem, the sum of these distances is 210 km:

2x + 2(x + 5) = 210

Solving for x: 2x + 2x + 10 = 210 4x + 10 = 210 4x = 200 x = 50

So, the speed of the slower train is 50 km/h and the speed of the faster train is 55 km/h.

Therefore, the speed of the slower train is 50 km/h and the speed of the faster train is 55 km/h.

This solution is based on the given problem and the calculations are derived accordingly.