Question

Пчёлы собирают нектар с клеверного поля-в 1200 м от пасеки и с луга-в 600 м от пасеки.От поля до посеки пчела летит на 2 мин дольше,чем от луга до посеки.Сколько времени тратит пчела на путь от поля до пасеки?Сколько времени тратит ппчела на путь от луга до ппосеки?

Answer 1

1200-600=600м пролетит пчела за 2 минуты
600 метров - это пол пути до клеверного поля
2*2=4 минуты до клеверного поля
до луга 600 м - то есть за 2 минуты

Answer 2

Calculating Bee Flight Time

To calculate the time spent by a bee flying from the clover field to the apiary and from the meadow to the apiary, we can use the given information.

Given: - Distance from the clover field to the apiary = 1200 m - Distance from the meadow to the apiary = 600 m - The bee takes 2 minutes longer to fly from the clover field to the apiary than from the meadow to the apiary.

Let's denote: - Time taken to fly from the meadow to the apiary as t minutes. - Time taken to fly from the clover field to the apiary as t + 2 minutes.

Using the formula: time = distance/speed

We can calculate the time taken by the bee to fly from the clover field to the apiary and from the meadow to the apiary.

Calculating Time from the Clover Field to the Apiary

The time taken by the bee to fly from the clover field to the apiary can be calculated using the given distance of 1200 m.

The formula for time is: time = distance/speed

Let's denote the speed of the bee as s m/min.

So, the time taken to fly from the clover field to the apiary is: t + 2 = 1200/s

Calculating Time from the Meadow to the Apiary

The time taken by the bee to fly from the meadow to the apiary can also be calculated using the given distance of 600 m.

Using the formula: time = distance/speed

The time taken to fly from the meadow to the apiary is: t = 600/s

Solving for Time

We have two equations: 1. t + 2 = 1200/s 2. t = 600/s

We can solve these equations to find the value of t and then calculate the time taken by the bee to fly from the clover field to the apiary and from the meadow to the apiary.

Let's solve for t.

Solution

Subtracting the second equation from the first equation: (t + 2) - t = (1200/s) - (600/s) 2 = 600/s s = 600/2 s = 300 m/min

Now, we can substitute the value of s back into the second equation to find t: t = 600/300 t = 2 minutes

So, the bee takes 2 minutes to fly from the meadow to the apiary, and 4 minutes to fly from the clover field to the apiary.

Therefore, the bee spends 4 minutes flying from the clover field to the apiary and 2 minutes flying from the meadow to the apiary.