Question

На 991 тысячу больше чем сумма наименьшего пятизначного числа и наибольшего шестизначного числа

Answer 1

Наибольшее шестизн. число 999999
наим пятизн 10000
их сумма ровна 1 009 999
прибавляем к этому числу 991тыс = 1 009 999 +991 000 = 2 000 999

Answer 2

Problem Analysis

The problem states that the sum of 991 thousand is greater than the sum of the smallest five-digit number and the largest six-digit number. We need to determine the values of the smallest five-digit number and the largest six-digit number and calculate their sum.

Solution

To find the smallest five-digit number, we need to find the smallest number with five digits. The smallest five-digit number is 10,000.

To find the largest six-digit number, we need to find the largest number with six digits. The largest six-digit number is 999,999.

Now, we can calculate the sum of the smallest five-digit number and the largest six-digit number:

10,000 + 999,999 = 1,009,999

Therefore, the sum of the smallest five-digit number and the largest six-digit number is 1,009,999.

Since the problem states that the sum of 991 thousand is greater than the sum of the smallest five-digit number and the largest six-digit number, we can conclude that:

991,000 > 1,009,999

Therefore, the statement in the problem is false.

Conclusion

The statement in the problem, which claims that 991 thousand is greater than the sum of the smallest five-digit number and the largest six-digit number, is false. The sum of the smallest five-digit number and the largest six-digit number is 1,009,999, which is greater than 991 thousand.