Question

В 3 резервуарах 120 т. воды. в 1 и 2 резервуарах 76 т. воды, а во 2 и 3 - 68 т. сколько тонн воды в каждом резервуаре

Answer 1

1)120- 76=44 (т)- в третьем резервуаре
2)68-44=24 (т)- во втором резервуаре
3)120-68=52 (т)- в первом резервуаре
Ответ: 44 т, 24 т, 52 т

Answer 2

В третьем резервуаре: 
120 - 76 = 44 ( т ) 
В первом резервуаре:
120 - 68 = 52 ( т ) 
Во втором резервуаре 
120 - ( 52 + 44 ) = 120 - 96 = 24 

Answer 3

Calculating Water Distribution in the Reservoirs

To calculate the amount of water in each reservoir, we can use a system of equations based on the given information.

Let's denote the amount of water in the first reservoir as x, in the second reservoir as y, and in the third reservoir as z.

We have the following information: - In the first and second reservoirs, there are 76 tons of water each: x + y = 76. - In the second and third reservoirs, there are 68 tons of water each: y + z = 68. - In total, there are 120 tons of water in all three reservoirs: x + y + z = 120.

Solving the System of Equations

We can solve this system of equations to find the amount of water in each reservoir.

Subtracting the second equation from the first, we get: x - z = 8.

Adding this result to the third equation, we get: 2x = 128.

So, x = 64.

Substituting x back into the first equation, we get: 64 + y = 76, which gives us y = 12.

Finally, substituting y into the second equation, we get: 12 + z = 68, which gives us z = 56.

Conclusion

Therefore, there are: - 64 tons of water in the first reservoir, - 12 tons of water in the second reservoir, and - 56 tons of water in the third reservoir.