Question

Периметр треугольника АВС равен 64см. сторона АВ меньше стороны АС на 7 см. но больше стороны ВС на 12см. Найдите длину каждой стороны треугольника АВС?

Answer 1

Пусть сторона АВ=х, тогда:
АС=АВ+7=х+7 см,
ВС=АВ-12=х-12,
Р=АВ+АС+ВС,
64=х+(х+7)+(х-12),
64=3х-5,
69=3х,
х=23
АВ=23(см),
АС=АВ+7=30(см),
ВС=АВ-12=11 (см).

Answer 2

Perimeter of Triangle ABC

To find the lengths of the sides of triangle ABC, we are given the following information:

- The perimeter of triangle ABC is 64 cm. - Side AB is 7 cm shorter than side AC. - Side AB is 12 cm longer than side BC.

Let's denote the lengths of the sides as follows: - Side AB = x cm - Side AC = (x + 7) cm - Side BC = (x - 12) cm

To find the lengths of the sides, we can use the formula for the perimeter of a triangle, which states that the perimeter is equal to the sum of the lengths of all three sides:

Perimeter of triangle ABC = AB + AC + BC

Substituting the lengths of the sides, we have:

64 cm = x cm + (x + 7) cm + (x - 12) cm

Simplifying the equation, we get:

64 cm = 3x - 5 cm

Now, let's solve for x:

3x - 5 cm = 64 cm

Adding 5 cm to both sides:

3x = 69 cm

Dividing both sides by 3:

x = 23 cm

Therefore, side AB is 23 cm, side AC is (23 + 7) cm = 30 cm, and side BC is (23 - 12) cm = 11 cm.

So, the lengths of the sides of triangle ABC are: - Side AB = 23 cm - Side AC = 30 cm - Side BC = 11 cm