Question

помогите решить задачку!) Магазин за 3 дня продал 1240,8 кг сахара.В первый день было продано 543 кг, во второй-в 2 раза больше,чем в третий. Сколько кг сахара продано в третий день?

Answer 1

232,6 кг сахара продано в третий день

Answer 2

пусть х это сахара продано в третий день тогда во второй 2х в первый 543 по условию всего сахара продано 1240.8 отсюда уравнение: х+2х+543=1240.8; 3х=697.8;х=232.6.    232.6кг продано в третий день

 

 

Answer 3

Problem Analysis

The problem states that a store sold 1240.8 kg of sugar over three days. On the first day, 543 kg were sold, and on the second day, the amount sold was twice that of the third day. We need to find out how much sugar was sold on the third day.

Solution

Let's denote the amount of sugar sold on the third day as x kg. We know that on the second day, the amount sold was twice that of the third day, so the amount sold on the second day was 2x kg. The total amount sold over the three days is 1240.8 kg.

So, we can set up the equation: 543 + 2x + x = 1240.8

Solving for x will give us the amount of sugar sold on the third day.

Calculation

Let's solve the equation: 543 + 2x + x = 1240.8

Combining like terms: 3x + 543 = 1240.8

Subtracting 543 from both sides: 3x = 1240.8 - 543 3x = 697.8

Dividing by 3: x = 697.8 / 3 x = 232.6

Answer

232.6 kg of sugar were sold on the third day.

I hope this helps! If you have any further questions, feel free to ask.