Question

Решите задачу на расстояний 2 км. 700 м. от дачного поселка находиться пруд. Игорь от пруда, а Олег от поселка выезжают на велосипедах одновременно навстречу друг другу и встречаются через 6 мин. найди скорость . с который ехал каждый из них, если скорость Олега на 50м/мин больше скорости Игоря

Answer 1

Х-скорость Игоря, х+50 скорость Олега Составляем уравнение
(х+50) умножить на 6 =2700метров
раскрываем скобки:  6х +300=2700
6х=2700-300
6х=2400
х=400м - скорость сближения 2 велосипедистов
400 :2 =200 м/мин была бы скорость каждого, но Олег ехал на 50 метров /мин  больше,
200+50 =250 м/мин - скорость Олега

Answer 2

2 км 700 м равно 2700 м
2700 : 6 = 450 м/мин скорость сближения Игоря и Олега
(450 - 50) : 2 = 200 м/мин скорость Игоря
200 + 50 = 250 м/мин скорость Олега

Answer 3

Problem Statement

You are given the following problem: Igor and Oleg leave from a dacha settlement towards a pond at the same time on their bicycles and meet each other after 6 minutes. The pond is located 2 km 700 m away from the dacha settlement. Oleg's speed is 50 m/min faster than Igor's. You need to find the speed at which each of them was traveling.

Solution

To solve this problem, we can use the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \]

Let's denote Igor's speed as \( S_I \) and Oleg's speed as \( S_O \). We know that the total distance traveled by both of them is 2 km 700 m, which is equal to 2700 m. Also, they meet after 6 minutes, which is equal to 6/60 = 0.1 hours.

We can set up the following equations based on the given information: 1. Igor's distance traveled: \( S_I \times 0.1 = 2700 \) 2. Oleg's distance traveled: \( S_O \times 0.1 = 2700 \) 3. Oleg's speed is 50 m/min faster than Igor's: \( S_O = S_I + 50 \)

We can solve these equations to find the speeds of Igor and Oleg.

Calculations

Let's start by solving the first equation: \[ S_I \times 0.1 = 2700 \] \[ S_I = \frac{2700}{0.1} \] \[ S_I = 27000 \]

Now, we can use the third equation to find Oleg's speed: \[ S_O = S_I + 50 \] \[ S_O = 27000 + 50 \] \[ S_O = 27050 \]

Answer

So, Igor's speed is 27000 m/h and Oleg's speed is 27050 m/h.