Question

Из своих жилищ навстречу друг другу одновременно вышли Братец Ёж и Братец Кролик и встретились через 12 мин после начала движения. с какой скоростью двигался Братец Ёж, если расстояние между их жилищами равно 136,8 м, а Братец Кролик шёл со скоростью 9,6 м/мин?

Answer 1

136,8 м:12 мин=11,4 м/мин (скорость сближения или сумма скоростей) (V=S:t)
11,4 м/мин-9,6 м/мин=1,8 м/мин
Ответ: скорость ежа 1,8 м/мин

Answer 2

Problem Analysis

We are given that Brother Hedgehog and Brother Rabbit left their homes simultaneously and met each other after 12 minutes of movement. The distance between their homes is 136.8 meters, and Brother Rabbit was moving at a speed of 9.6 m/min. We need to find the speed at which Brother Hedgehog was moving.

Solution

Let's assume that Brother Hedgehog was moving at a speed of x m/min. We can use the formula `speed = distance / time` to find the speed of Brother Hedgehog.

The time taken by Brother Hedgehog to cover the distance is the same as the time taken by Brother Rabbit, which is 12 minutes.

Using the formula, we have:

x = distance / time

Substituting the given values:

x = 136.8 m / 12 min

Calculating the value:

x = 11.4 m/min

Therefore, Brother Hedgehog was moving at a speed of 11.4 m/min.

Answer

Brother Hedgehog was moving at a speed of 11.4 m/min.