Question

Периметр прямоугальника равен 20 см . Длина в пять раз больше ширины .Найти длину и ширину прямоугольника

Answer 1

Р=2(а+в), пусть ширина х, тогда

20=2(х+5х)

6х=20/2

х=10/6

х=1,67см ширина

1,67*5=8,35см длина

Answer 2

Perimeter of a Rectangle

To find the length and width of a rectangle given its perimeter, we need to set up a system of equations based on the given information.

Let's denote the length of the rectangle as L and the width as W.

According to the problem, the perimeter of the rectangle is 20 cm. The formula for the perimeter of a rectangle is given by:

Perimeter = 2(L + W)

Substituting the given value of the perimeter (20 cm) into the equation, we get:

20 = 2(L + W)

We are also given that the length is five times the width:

L = 5W

Now we can solve the system of equations to find the values of L and W.

Solving the System of Equations

Substituting the value of L from the second equation into the first equation, we have:

20 = 2(5W + W)

Simplifying the equation, we get:

20 = 2(6W)

20 = 12W

Dividing both sides of the equation by 12, we find:

W = 20/12

Simplifying the fraction, we get:

W = 5/3 cm

Substituting this value back into the second equation to find the length, we have:

L = 5(5/3)

Simplifying the expression, we get:

L = 25/3 cm

Therefore, the width of the rectangle is 5/3 cm and the length is 25/3 cm.

Answer

The width of the rectangle is 5/3 cm and the length is 25/3 cm.