Question

В 5а и 5в классах учатся 51 школьник а в 5а и 5б 52 школьника, в 5б и 5в - 53 школьника. Сколько учеников в каждом классе?

Answer 1

А + в = 51
а + б = 52
б + в = 53
Заметим, что каждая буква повторяется по 2 раза.
То есть "полный комплект" 5а + 5б + 5в: 1). (51 + 52 + 53) : 2 = 78 (уч.)
Тогда 5б: 2). 78 - 51= 27 (уч.),
          5в: 3) 53 - 27 = 26 (уч.)
          5а: 4) 52 - 27 = 25 (уч.)

Answer 2

Let's solve the problem step by step:

1) We know that in 5a and 5b classes there are 51 + 52 = 103 students. 2) In 5a and 5v classes, there are 51 + 53 = 104 students. 3) To find the number of students in each class, we need to find the number of students in 5a, 5b, and 5v separately.

Let's assume the number of students in 5a class is x.

So, the number of students in 5b class is x + 1 (adding 1 additional student from 5a class). And the number of students in 5v class is x + 2 (adding 2 additional students from 5a class).

Now we can create an equation:

x + (x + 1) + (x + 2) = 103

Combining like terms, we have:

3x + 3 = 103

Subtracting 3 from both sides, we get:

3x = 100

Dividing both sides by 3, we find:

x = 33.33

Since we cannot have decimal numbers for the number of students, we can round down the value of x to 33.

Therefore, there are 33 students in 5a class, 33 + 1 = 34 students in 5b class, and 33 + 2 = 35 students in 5v class.