
1.вычислить: 10+1,6:(3/5*0,4-0,4)*(4/9-2/3) 2.даны множества: A={1;2;3;4;5;6;7;8;9},
B={5;6;7;8;9;10;11;12}. найдите: A u B , A ^ B , A\B, B\A. 3.вычислите производную функции: 6x+1 y= ------ 5x

Ответы на вопрос




1. To compute the expression, let's break it down step by step:
Expression: 10 + 1.6 / (3/5 * 0.4 - 0.4) * (4/9 - 2/3) + 2
Step 1: Simplify the innermost parentheses: 3/5 * 0.4 = 0.24
Step 2: Simplify the expression inside the parentheses: (0.24 - 0.4) = -0.16
Step 3: Simplify the outermost parentheses: 4/9 - 2/3 = (4/9) - (6/9) = -2/9
Step 4: Substitute the simplified values back into the expression: 10 + 1.6 / (-0.16) * (-2/9) + 2
Step 5: Simplify the multiplication and division: 1.6 / (-0.16) = -10 -10 * (-2/9) = 20/9
Step 6: Substitute the simplified values back into the expression: 10 + 20/9 + 2
Step 7: Combine the fractions: 20/9 + 10/1 + 18/9 = (20 + 90 + 18) / 9 = 128/9
Therefore, the value of the expression is 128/9.
2. Let's find the required sets:
Given sets: A = {1, 2, 3, 4, 5, 6, 7, 8, 9} B = {5, 6, 7, 8, 9, 10, 11, 12}
A union B (A U B): A U B = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}
A intersection B (A ∩ B): A ∩ B = {5, 6, 7, 8, 9}
A set difference B (A \ B): A \ B = {1, 2, 3, 4}
B set difference A (B \ A): B \ A = {10, 11, 12}
Therefore, A U B = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, A ∩ B = {5, 6, 7, 8, 9}, A \ B = {1, 2, 3, 4}, B \ A = {10, 11, 12}.
3. To find the derivative of the function, let's differentiate it with respect to x:
Function: 6x + 1 + y = 5x
Step 1: Rearrange the equation to isolate y: y = 5x - 6x - 1 y = -x - 1
Step 2: Differentiate both sides of the equation with respect to x: d/dx(y) = d/dx(-x - 1)
Step 3: Differentiate each term: d/dx(y) = d/dx(-x) - d/dx(1)
Step 4: Apply the power rule and constant rule of differentiation: d/dx(y) = -1 - 0
Step 5: Simplify the derivative: d/dx(y) = -1
Therefore, the derivative of the function 6x + 1 + y = 5x with respect to x is -1.


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