Question

Из школы в разные стороны вышли два ученика скорость первого 50 м/мин скорость второго 60 м/мин через какое время расстояние между ними будет равно 330 метров

Answer 1

50+60=110 м/мин
330:110= 3 мин
Ответ: 3 минуты

Answer 2

Problem Analysis

Two students leave school in different directions. The first student has a speed of 50 m/min, and the second student has a speed of 60 m/min. We need to determine the time it takes for the distance between them to be 330 meters.

Solution

To solve this problem, we can use the formula: distance = speed × time. We'll calculate the time it takes for each student to travel a certain distance and find the time when the distance between them is 330 meters.

Let's calculate the time it takes for the first student to travel a distance of 330 meters: - Distance = 330 meters - Speed = 50 m/min - Time = Distance / Speed = 330 / 50 = 6.6 minutes

Now, let's calculate the time it takes for the second student to travel a distance of 330 meters: - Distance = 330 meters - Speed = 60 m/min - Time = Distance / Speed = 330 / 60 = 5.5 minutes

Therefore, the distance between the two students will be equal to 330 meters after approximately 5.5 minutes.

Answer

The distance between the two students will be equal to 330 meters after approximately 5.5 minutes.