Question

В школьном чемпионате по футболу было сыграно 10 матчей. команда факел выиграла 3 матча, команда зенит на 2 матча больше , чем команда факел. а остальные матчи выиграла команда чайка. найти решение

Answer 1

3+2=5 матчей выиграла команда зенит.
5+3=8 матчей выиграли команды факел и зенит.
10-8=2 матча выиграла команда чайка.

Answer 2

Problem Analysis

In a school football championship, there were a total of 10 matches played. The team "Fakel" won 3 matches, while the team "Zenit" won 2 matches more than "Fakel". The remaining matches were won by the team "Chaika". We need to find a solution based on this information.

Solution

Let's break down the information given:

- The team "Fakel" won 3 matches. - The team "Zenit" won 2 matches more than "Fakel". - The remaining matches were won by the team "Chaika".

To find the number of matches won by "Zenit," we need to add 2 to the number of matches won by "Fakel." Therefore, "Zenit" won 3 + 2 = 5 matches.

The remaining matches were won by "Chaika." Since there were a total of 10 matches played and "Fakel" won 3 matches and "Zenit" won 5 matches, the number of matches won by "Chaika" can be calculated as follows:

Total matches - (Matches won by Fakel + Matches won by Zenit) = 10 - (3 + 5) = 2 matches.

Therefore, the team "Chaika" won 2 matches.

To summarize: - The team "Fakel" won 3 matches. - The team "Zenit" won 5 matches. - The team "Chaika" won 2 matches.

Please let me know if there is anything else I can help you with!