Question

Решите уравнения : 1. (2х-5) / (3х+1) = -(1/7) 2. (2х-5) / (3х+1) = 7/2

Answer 1

Вот держи надеюсь помог

Answer 2

1. (2х-5)/(3х+1) = -(1/7)

To solve this equation, you can start by multiplying both sides of the equation by 7 to eliminate the fraction:

7(2х-5)/(3х+1) = -1

Then, distribute the 7 on the left side:

(14х - 35)/(3х + 1) = -1

Next, get rid of the fraction by multiplying both sides by (3х + 1):

(3х + 1)(14х - 35)/(3х + 1) = -1(3х + 1)

Simplifying the left side:

14х - 35 = -3х - 1

Then, add 3х to both sides of the equation:

14х - 3х - 35 = -1

Combine like terms:

11х - 35 = -1

Add 35 to both sides:

11х = 34

Finally, divide both sides by 11 to solve for х:

х = 34/11

So the solution to the equation is х = 34/11.

2. (2х-5)/(3х+1) = 7/2

To solve this equation, follow similar steps as the previous one:

2(2х-5)/(3х+1) = 7/2

Multiplying through by 2 to get rid of the fraction:

(4х - 10)/(3х + 1) = 7/2

Next, multiply both sides by (3х + 1):

(3х + 1)(4х - 10)/(3х + 1) = 7/2(3х + 1)

Simplifying the left side:

4х - 10 = (7/2)(3х + 1)

Expanding the right side:

4х - 10 = (21х + 7)/2

To get rid of the fractions, multiply both sides by 2:

2(4х - 10) = 21х + 7

Distribute the 2 on the left side:

8х - 20 = 21х + 7

Next, subtract 8х from both sides:

-20 = 13х + 7

Subtract 7 from both sides:

-27 = 13х

Finally, divide both sides by 13 to solve for х:

х = -27/13

So the solution to the equation is х = -27/13.