
Сума довжени всих ребер прямоктного паралелепипеда -- 160дм ' а два його вимири 12 дм и 15 дм
знайды 3 вимир парелелепипеда и його обем знайди масу якщо його виготовлено зи скла и маса 1см³ скла доринюэ 3г

Ответы на вопрос

27+х=40
х=13дм-3 измерение
12*15*13=2340дм³ объем
2340*3=7020г масса



Calculation of the Sum of all Edges of a Rectangular Parallelepiped
To find the sum of all edges of a rectangular parallelepiped, we need to know the lengths of its three dimensions. In this case, the given dimensions are 12 dm, 15 dm, and 160 dm.To calculate the sum of all edges, we can use the formula: Sum of all edges = 4 * (Length + Width + Height).
Let's substitute the given values into the formula and calculate the sum of all edges: Sum of all edges = 4 * (12 dm + 15 dm + 160 dm).
Calculating the sum of all edges: Sum of all edges = 4 * (187 dm) = 748 dm.
Therefore, the sum of all edges of the rectangular parallelepiped is 748 dm.
Calculation of the Volume of the Parallelepiped
To find the volume of the parallelepiped, we can use the formula: Volume = Length * Width * Height.Substituting the given values into the formula, we can calculate the volume: Volume = 12 dm * 15 dm * 160 dm.
Calculating the volume: Volume = 28,800 dm³.
Therefore, the volume of the parallelepiped is 28,800 dm³.
Calculation of the Mass of the Parallelepiped
To calculate the mass of the parallelepiped, we need to know the material it is made of and the mass of 1 cm³ of that material. In this case, the parallelepiped is made of glass, and the mass of 1 cm³ of glass is given as 3 g.To find the mass of the parallelepiped, we can use the formula: Mass = Volume * Mass per cm³.
Substituting the given values into the formula, we can calculate the mass: Mass = 28,800 dm³ * (3 g/cm³).
Converting dm³ to cm³: 1 dm³ = 1000 cm³.
Calculating the mass: Mass = 28,800 dm³ * (3 g/cm³) * (1000 cm³/dm³) = 86,400,000 g.
Therefore, the mass of the parallelepiped is 86,400,000 g.
Please note that the given dimensions and calculations are based on the information provided in the question.


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