Question

Два шкива соеденены приводным ремнем.Длина окружности большего шкива 54см.а меньшего 36см.Больший шкив делает 30 оборотов в минуту.Сколько оборотов в минуту делает меньший шкив?

Answer 1

54/30=1,8 делает 1 оборот большой шкив
36/1,8=20 оборотов делает меньший шкив в минуту
ответ: 20 оборотов в минуту.

Answer 2

Calculation of the Number of Revolutions per Minute for the Smaller Pulley

To calculate the number of revolutions per minute (RPM) for the smaller pulley, we can use the relationship between the circumferences of the two pulleys and the number of revolutions made by the larger pulley.

The ratio of the circumferences of the two pulleys is equal to the ratio of the number of revolutions made by each pulley. In other words, the ratio of the circumference of the larger pulley to the circumference of the smaller pulley is equal to the ratio of the number of revolutions made by the larger pulley to the number of revolutions made by the smaller pulley.

Let's denote the number of revolutions made by the smaller pulley as 'x'. Given that the circumference of the larger pulley is 54 cm and the circumference of the smaller pulley is 36 cm, we can set up the following equation:

54 cm / 36 cm = 30 RPM / x RPM

To find the value of 'x', we can cross-multiply and solve for 'x':

54 cm * x RPM = 36 cm * 30 RPM

Dividing both sides of the equation by 54 cm:

x RPM = (36 cm * 30 RPM) / 54 cm

Simplifying the equation:

x RPM = 20 RPM

Therefore, the smaller pulley makes 20 revolutions per minute.