Question

Решить с помощью "Поиска Решения" старинную задачу: Крестьянин на базаре за 100 рублей купил 100 голов скота. Бык стоит 5 рублей, корова 2 рубля,10 овец стоят 1 рубль. Сколько быков, коров и овец купил крестьянин?

Answer 1

9 быков 25 коров 50 овец

Answer 2

Solving the Problem Using "Search for Solution"

To solve the problem of how many bulls, cows, and sheep the peasant bought, we can use the given information about the total number of animals and their respective prices.

Let's denote: - B as the number of bulls - C as the number of cows - S as the number of sheep

We are given the following information: 1. The peasant bought 100 animals in total. 2. The total cost of the animals was 100 rubles. 3. The price of a bull is 5 rubles. 4. The price of a cow is 2 rubles. 5. The price of 10 sheep is 1 ruble.

We can set up the following equations based on the given information: 1. B + C + S = 100 (Total number of animals) 2. 5B + 2C + (1/10)S = 100 (Total cost of the animals)

Now, let's solve these equations to find the values of B, C, and S.

Solution

Using the given equations, we can solve for the values of B, C, and S.

1. From the equation B + C + S = 100, we can express S in terms of B and C as S = 100 - B - C.

2. Substituting S = 100 - B - C into the equation 5B + 2C + (1/10)S = 100, we get 5B + 2C + (1/10)(100 - B - C) = 100.

3. Simplifying the equation, we get 50B + 20C + 10 - B - C = 100.

4. Combining like terms, we have 49B + 19C = 90.

5. Given that B and C are both positive integers, we can start by trying different values for B and solving for C to find the valid solutions.

Conclusion

By solving the given equations, we can find the values of B, C, and S that satisfy the conditions of the problem.