Question

Восстановите примеры,считая,что одинаковые буквы обозначают одинаковые цифры,а разные буквы-разные цифры:б3б+76б=а300; а4а+33а=б084; удар+удар=драка; деталь+деталь=изделие

Answer 1

Б3б+76б=а300
535+765 = 1300


а4а+33а=б084
747+337 = 1084


удар+удар=драка
8126+8126=16252

с детаями справиться не смог - замучился совсем)

Answer 2

Solving the Equations:

To solve the given equations, we need to assign unique digits to each letter in a way that satisfies the given conditions. Let's analyze each equation one by one.

1. б3б + 76б = а300:

In this equation, the letters б and а represent different digits, while the letter б represents the same digit. To find the values of these digits, we can start by examining the units place. Since б + 6 = 0 (in the units place), the only possible value for б is 4. Now, substituting б = 4 into the equation, we have:

443 + 764 = а300

Simplifying the equation, we get:

1207 = а300

Since а represents a different digit, we can conclude that а = 1. Therefore, the solution to the equation is:

б = 4 and а = 1.

2. а4а + 33а = б084:

Similar to the previous equation, in this equation, the letters а and б represent different digits, while the letter а represents the same digit. Let's analyze the units place first. Since а + 3 = 4 (in the units place), the only possible value for а is 1. Substituting а = 1 into the equation, we have:

1 41 + 33 1 = б084

Simplifying the equation, we get:

174 + 331 = б084

Adding the numbers on the left side, we have:

505 = б084

Since б represents a different digit, we can conclude that б = 5. Therefore, the solution to the equation is:

а = 1 and б = 5.

3. удар + удар = драка:

In this equation, each letter represents a different digit. We need to find the values of у, д, а, and р that satisfy the equation. Since the sum of two identical numbers cannot be greater than 18 (the maximum value for a single digit), we can conclude that у + у = д. Therefore, the value of д must be an even number. Additionally, since the sum of two digits cannot exceed 19, the value of д must be less than or equal to 9.

Let's consider the possible values for д:

- If д = 2, then у + у = 2, which is not possible since the sum of two identical digits cannot be 2. - If д = 4, then у + у = 4, which is not possible since the sum of two identical digits cannot be 4. - If д = 6, then у + у = 6, which is not possible since the sum of two identical digits cannot be 6. - If д = 8, then у + у = 8, which is possible if у = 4.

Therefore, the solution to the equation is:

у = 4 and д = 8.

Substituting these values back into the equation, we have:

48ар + 48ар = 8рака

Simplifying the equation, we get:

96ар = 8рака

Dividing both sides of the equation by 8, we have:

12ар = рака

Since а, р, and к represent different digits, we can conclude that:

а = 1, р = 2, and к = 6.

Therefore, the solution to the equation is:

у = 4, д = 8, а = 1, р = 2, and к = 6.

4. деталь + деталь = изделие:

In this equation, each letter represents a different digit. We need to find the values of д, е, т, а, л, и, and з that satisfy the equation.

Since the sum of two identical numbers cannot be greater than 18 (the maximum value for a single digit), we can conclude that д + д = и. Therefore, the value of и must be an even number. Additionally, since the sum of two digits cannot exceed 19, the value of и must be less than or equal to 9.

Let's consider the possible values for и:

- If и = 2, then д + д = 2, which is not possible since the sum of two identical digits cannot be 2. - If и = 4, then д + д = 4, which is not possible since the sum of two identical digits cannot be 4. - If и = 6, then д + д = 6, which is not possible since the sum of two identical digits cannot be 6. - If и = 8, then д + д = 8, which is possible if д = 4.

Therefore, the solution to the equation is:

д = 4 and и = 8.

Substituting these values back into the equation, we have:

48еталь + 48еталь = 8зеталь

Simplifying the equation, we get:

96еталь = 8зеталь

Dividing both sides of the equation by 8, we have:

12еталь = зеталь

Since е, т, а, л, and з represent different digits, we can conclude that:

е = 1, т = 2, а = 3, л = 5, and з = 6.

Therefore, the solution to the equation is:

д = 4, е = 1, т = 2, а = 3, л = 5, and з = 6.

Summary of Solutions:

The solutions to the given equations are as follows:

1. б3б + 76б = а300: - б = 4 - а = 1

2. а4а + 33а = б084: - а = 1 - б = 5

3. удар + удар = драка: - у = 4 - д = 8 - а = 1 - р = 2 - к = 6

4. деталь + деталь = изделие: - д = 4 - е = 1 - т = 2 - а = 3 - л = 5 - и = 8 - з = 6