Question

В семье четверо детей их возвраст 5,8,13и15лет а зовут их Таня,Юра,Света и Лена. Одна девочка ходит в детский сад,Таня старше,Юры,а сумма лет Тани и Светы делится на три. Сколько лет Лене?

Answer 1

Сдесь только уравнением

Answer 2

Family Puzzle

Let's break down the information provided to solve the puzzle.

- There are four children in the family: Tanya, Yura, Sveta, and Lena. - Their ages are 5, 8, 13, and 15 years old. - One of the girls goes to kindergarten. - Tanya is older than Yura. - The sum of Tanya's and Sveta's ages is divisible by three.

Solution

1. Identify the Kindergartener: - Since one of the girls goes to kindergarten, and Lena is the only girl left, Lena must be the one who goes to kindergarten.

2. Determine Tanya's Age: - Tanya is older than Yura, so she can't be 5 years old. Therefore, Tanya is 8 or 13 years old. - The sum of Tanya's and Sveta's ages is divisible by three, so Tanya and Sveta's ages could be (8, 13) or (13, 15). - If Tanya is 8 years old, Sveta would be 13, and their sum (8 + 13) is not divisible by 3. - If Tanya is 13 years old, Sveta would be 15, and their sum (13 + 15) is divisible by 3.

3. Calculate Lena's Age: - Since Lena is the only one left, she must be 5 years old.

So, Lena is 5 years old.

This solution satisfies all the given conditions.