Question

Чему равна масса воды полного аквариума , имеющего форму прямоугольного параллелепипеда, если площадь его основания 842 см2 , а высота 3дм 5см (1 см3 воды имеет массу 1 г ; толщенной стенок аквариума пренебречь) ?

Answer 1

842*35= 29470 кв.см

29,47 кг

Answer 2

Calculating the Mass of Water in the Aquarium

To calculate the mass of water in the aquarium, we can use the formula:

mass = volume × density

First, we need to calculate the volume of the water in the aquarium.

The volume of a rectangular parallelepiped (prism) is given by the formula:

volume = base area × height

Given: - Base area = 842 cm² - Height = 3 dm 5 cm = 35 cm

Let's calculate the volume of the water in the aquarium:

volume = 842 cm² × 35 cm = 29470 cm³

Now, we need to convert the volume from cubic centimeters to liters, as 1 liter is equal to 1000 cubic centimeters.

volume = 29470 cm³ ÷ 1000 = 29.47 liters

Now that we have the volume, we can calculate the mass of the water using the given density of water, which is 1 g/cm³.

mass = 29.47 liters × 1000 g/liter = 29470 grams

So, the mass of water in the aquarium is 29470 grams.