Question

Срочно! нужно решить задачу по высшей математике! в подробном виде,даю 70 баллов Даны 40 чисел,из них 10 чисел кратны 3,15 чисел кратны 2,20 числе не кратны ни 2 и не 3,сколько среди 40 чисел кратны 6 ?

Answer 1

Это не высшая математика, а младшая школа )
Числа кратные 6 - это числа, которые кратны одновременно 2 и 3.
Пусть их х штук.
Тогда чисел кратных 3 но не кратных 2 будет 10-х штук.
Чисел кратных 2, но  не кратных 3 будет 15-х штук.
Поэтому количество чисел кратных 2 или 3 будет
х+(10-х)+(15-х)=40-20.
25-х=20
х=5.

Answer 2

Problem Analysis

To solve this problem, we need to find the number of integers among the given 40 numbers that are divisible by 6. We are given that: - 10 numbers are divisible by 3. - 15 numbers are divisible by 2. - 20 numbers are neither divisible by 2 nor divisible by 3.

Solution

Let's break down the problem step by step:

Step 1: Find the number of numbers divisible by 3 and 2. - Since 10 numbers are divisible by 3 and 15 numbers are divisible by 2, we can conclude that there are at least 10 numbers that are divisible by both 2 and 3. This is because any number divisible by 6 (which is the least common multiple of 2 and 3) will be divisible by both 2 and 3.

Step 2: Find the number of numbers that are neither divisible by 2 nor divisible by 3. - We are given that 20 numbers are neither divisible by 2 nor divisible by 3.

Step 3: Find the number of numbers divisible by 6. - To find the number of numbers divisible by 6, we need to subtract the number of numbers that are neither divisible by 2 nor divisible by 3 from the number of numbers divisible by both 2 and 3. - Therefore, the number of numbers divisible by 6 is at least 10 - 20 = -10.

Answer

Based on the given information, it seems that there is a contradiction in the problem statement. The number of numbers divisible by 6 cannot be negative. Please double-check the problem statement and provide accurate information to solve the problem correctly.

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