Question

В 11 ч с аэродрома вылетели одновременно в противоположных направленияхдва самолета.В 14 ч расстояние между ними было 3540км. Одиниз них летел со скоростью 620км/ч.С какой средней скоростью летел другой самолет?

Answer 1

14-11=3(ч)t                                    620x3=1860(км)s 1-го самолета                          3540-1860=1680(км)s 2-го самолета                      1680/3=560(км/ч)V 2-го самолета

Answer 2

1) 14-11=3 час время в пути

2) 620*3=1860км пролетел один из самолетов за 3 часа

3) 3540-1860= 1680км пролетел другой самолет за три часа

4) 1680:3= 560 км скорость второго самолета

 

Ответ: скорость второго самолета 560 км/час 

Answer 3

Problem Analysis

We have two planes that took off simultaneously from an airport in opposite directions. At 14:00, the distance between them was 3540 km. One of the planes was flying at a speed of 620 km/h. We need to find the average speed of the other plane.

Solution

Let's assume the average speed of the other plane is x km/h.

We know that the time it took for the planes to be 3540 km apart is 3 hours (from 11:00 to 14:00).

Using the formula distance = speed × time, we can set up the following equation for the first plane:

3540 km = 620 km/h × 3 hours

Simplifying the equation, we find:

3540 km = 1860 km

Therefore, the first plane traveled 1860 km in 3 hours.

Now, let's set up the equation for the second plane:

3540 km = x km/h × 3 hours

To find the average speed of the second plane, we can solve for x:

x = 3540 km / 3 hours

Calculating the value, we find:

x = 1180 km/h

Therefore, the average speed of the second plane was 1180 km/h.

Answer

The average speed of the second plane was 1180 km/h.