Question

Имеется 735 г 16%-го раствора йода в спирте. Сколько нужно добавить к имеющемуся раствору спирта, чтобы получить 10%-й раствор.

Answer 1

     Решение:Есть 735*0.16=117.6 (г) - йода в спирте
117.6г - 10%
хг - 100%

117.6/х=10/100
х=100*117.6/10=1176г - весит 10%-ный раствор
1176-735=441 - вес спирта которий долили.

Answer 2

Calculating the Amount of Solution to Add

To calculate the amount of pure alcohol needed to obtain a 10% solution from a 16% solution, we can use the following formula:

C1V1 = C2V2

Where: - C1 = concentration of the initial solution - V1 = volume of the initial solution - C2 = concentration of the final solution - V2 = volume of the final solution

In this case, we have: - C1 = 16% (or 0.16 as a decimal) - V1 = 735g - C2 = 10% (or 0.10 as a decimal) - V2 = the unknown amount of pure alcohol to be added

Using the formula, we can solve for V2:

V2 = (C1V1) / C2

Calculation

V2 = (0.16 * 735g) / 0.10

Let's calculate the value of V2.