Question

Из города А в 8ч утра вышел грузовик со скоростью 32 км/ч, а в 11ч вслед за ним выехал автобус со скоростью 56км/ч.В какое время и на каком расстоянии от города А автобус догонит грузовик?

Answer 1

32*3=96 км
56-32=24 км/ час приближ автобус
(96:24)+11= 15 часов догонит грузовик
96+(4*56)=320 км такое будет расстояние от города

Answer 2

Problem Analysis

We are given that a truck leaves city A at 8:00 AM with a speed of 32 km/h, and a bus leaves city A at 11:00 AM with a speed of 56 km/h. We need to determine at what time and at what distance from city A the bus will catch up to the truck.

Solution

To solve this problem, we can use the formula:

Time = Distance / Speed

Let's assume that the bus catches up to the truck after time 't' hours. During this time, the truck would have traveled a distance of 32t km, and the bus would have traveled a distance of 56t km.

Since the bus catches up to the truck, the distances traveled by both vehicles must be equal. Therefore, we can set up the following equation:

32t = 56t

Simplifying the equation, we get:

56t - 32t = 0

24t = 0

From this equation, we can see that the time 't' is equal to 0. This means that the bus catches up to the truck at the same time they both start their journey, which is 8:00 AM.

To find the distance at which the bus catches up to the truck, we can substitute the value of 't' into either the distance traveled by the truck or the bus. Let's use the distance traveled by the truck, which is 32t km:

Distance = 32t = 32 * 0 = 0 km

Therefore, the bus catches up to the truck at 8:00 AM and at a distance of 0 km from city A.

Answer

The bus will catch up to the truck at 8:00 AM and at a distance of 0 km from city A.