Question

Прямые АА1, ВВ1, СС1 не лежат в одной плоскости и имеют общую точку, АВ || А1В1, ВС || В1С1. Докажите, что АС || А1С1.

Answer 1

Ответ:  решение на фото :

Пошаговое объяснение:

Answer 2

Given Information:

We are given that lines AA1, BB1, and CC1 do not lie in the same plane and have a common point. Additionally, AB || A1B1 and BC || B1C1.

To Prove:

We need to prove that AC || A1C1.

Proof:

To prove that AC || A1C1, we can use the concept of transversals and parallel lines. If two lines are parallel to the same line, then they are parallel to each other.

From the given information, we know that AB || A1B1 and BC || B1C1. Let's consider line AB and line BC as transversals.

According to the transversal property, if AB || A1B1 and BC || B1C1, then AC || A1C1.

Therefore, we can conclude that AC || A1C1.

This completes the proof.

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