Question

Помогите решить задачу. Два самолета летели с одинаковой скоростью. Первый самолет был в воздухе 4 часа, второй 6 часов. Первый самолет пролетел на 1 400 км меньше второго. Какое расстояние пролетел каждый самолет

Answer 1

1400:(6-4)=700(км/ч) скорость
700*4=2800(км) первый
700*6=4200(км) второй

Answer 2

На 6-4=2 ч второй самолет летел дольше
1400÷2=700 км/ч скорость самолетов
700×4=2800 км пролетел первый самолет
2800+1400=4200 км пролетел второй самолет

Answer 3

Problem Analysis

We are given two airplanes that flew at the same speed. The first airplane was in the air for 4 hours, while the second airplane was in the air for 6 hours. The first airplane flew 1,400 km less than the second airplane. We need to find the distance traveled by each airplane.

Solution

Let's assume the distance traveled by the first airplane is x km. Since the second airplane flew 1,400 km more, the distance traveled by the second airplane is x + 1,400 km.

We can set up the following equation based on the given information:

4x = 6(x + 1,400)

Now, let's solve this equation to find the value of x.

Calculation

Expanding the equation:

4x = 6x + 8,400

Rearranging the equation:

6x - 4x = 8,400

Simplifying:

2x = 8,400

Dividing both sides by 2:

x = 4,200

Therefore, the first airplane traveled 4,200 km, and the second airplane traveled 4,200 + 1,400 = 5,600 km.

Answer

The first airplane traveled 4,200 km, and the second airplane traveled 5,600 km.