Question

Длина ломанной линии АВСД 24 дм. Длина звена ВС в 2 раза больше длины звена АВ. Длина СД 6 дм. Найдите длины звеньев АВ и ВС.

Answer 1

AB+BC+CД=24 дм;
АВ - х дм;
ВС - 2х дм;
СД=6 дм;

х+2х+6=24;
3х=24-6;
3х=18;
х=6 дм;
АВ=6дм;
ВС=2×6=12 (дм);

Answer 2

Given Information:

- Length of line segment ABSD is 24 dm. - Length of segment VS is twice the length of segment AB. - Length of segment SD is 6 dm.

Solution:

To find the lengths of segments AB and VS, we can use the given information and apply some basic geometry principles.

Let's assume the length of segment AB is x dm. Since the length of segment VS is twice the length of segment AB, the length of segment VS is 2x dm.

We know that the length of line segment ABSD is 24 dm. This means that the sum of the lengths of segments AB, BS, and SD is equal to 24 dm.

So, we can set up the following equation: x + 2x + 6 = 24

Simplifying the equation: 3x + 6 = 24 3x = 18 x = 6

Therefore, the length of segment AB is 6 dm and the length of segment VS is 12 dm.

Answer:

The length of segment AB is 6 dm and the length of segment VS is 12 dm.