Question

X^2+4x+53=0 решите пожалуйста

Answer 1

Может таком виде смотри

Answer 2

Quadratic Equation Solution

To solve the quadratic equation x^2 + 4x + 53 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

In this case, the coefficients are: - a = 1 - b = 4 - c = 53

Using the quadratic formula, we can calculate the solutions for x.

The solutions are: x = -2 + 7i and x = -2 - 7i.

This means that the solutions are complex numbers, indicating that the quadratic equation does not have real roots.

If you have any further questions or need additional assistance, feel free to ask!