Question

Велосипеды участовали в трёхдневном велопробеге. Во второй и третий день они проехали соответственно 120% и 4/5 расстояния, которое они преодолели за первый день. Какой путь они проехали в первый день, если длина всего маршрута составляет 270км?

Answer 1

120%=1,2
4/5=0,8,значит
в первый день х
во второй день 1,2х
в третий день 0,8х
всего 270 км
составим уравнение
х+1,2х+0,8х=270
3х=270
х=270:3
х=90 км проехали в первый день
============================

Answer 2

Calculation of the Distance Traveled on Each Day

To find out the distance traveled on the first day of the three-day cycling event, we need to calculate the distances covered on the second and third days.

According to the information provided, on the second day, the cyclists covered 120% of the distance they traveled on the first day. On the third day, they covered 4/5 of the distance they traveled on the first day.

Let's denote the distance traveled on the first day as x.

On the second day, the distance covered is 120% of x, which can be calculated as 1.2x.

On the third day, the distance covered is 4/5 of x, which can be calculated as (4/5)x.

The total distance of the three-day cycling event is given as 270 km.

To find the distance traveled on the first day, we can set up the following equation:

x + 1.2x + (4/5)x = 270

Simplifying the equation:

2.2x + (4/5)x = 270

Combining like terms:

(11/5)x = 270

To solve for x, we can multiply both sides of the equation by 5/11:

x = (270 * 5) / 11

Evaluating the expression:

x ≈ 122.73 km

Therefore, the cyclists traveled approximately 122.73 km on the first day of the three-day cycling event.