Question

Два ученика вышли одновременно из своих домов навстречу друг другу.Первый ученик шел со скоростью 60 м/мин и прошел до встречи 480 М. Скорость второго ученика на 10 м/мин больше скорости первого.Какое расстояние до встречи прошел второй ученик?

Answer 1

1)480:60=8 мин
2)60+10=70м/мин
3)70*8=560м
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1) 420/60=7(мин)-шла первая девочка2)70*7=490(м)-прошла вторая девочка

Либо так либо так...

Answer 2

1)480:60=8 мин
2)60+10=70м/мин
3)70*8=560м

Answer 3

Problem Analysis

We are given that two students leave their homes simultaneously and walk towards each other. The first student walks at a speed of 60 m/min and covers a distance of 480 m before they meet. The second student walks at a speed that is 10 m/min faster than the first student. We need to find the distance covered by the second student before they meet.

Solution

Let's assume that the second student covers the distance to the meeting point in time 't' minutes. Since the first student covers a distance of 480 m in the same time, we can set up the following equation:

Distance covered by the first student = Distance covered by the second student

60 * t = (60 + 10) * t

Simplifying the equation, we get:

60t = 70t

Dividing both sides by 10t, we get:

6 = 7

This equation is not true, which means there is no solution. It seems that there is an error in the problem statement or the given information. Please double-check the problem statement or provide additional information to proceed with the solution.

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