Question

Помогите решить задачу пж, 2 пешехода вышли одновременно на встречу друг к другу, и встретились через 3 часа , расстояние между поселками 30км,найдите скорость каждого пешехода, если у 1 она меньше на 2 ем\ч чем у другого

Answer 1

Скорость = путь : время.
Скорость сближения = 30 (км) : 3 (часа) = 10 (км/час)

Поскольку "скорость первого пешехода меньше на 2 , чем у другого", то (х-2)+х=10
2х=12 и х=6 (км/час, скорость второго пешехода).

Скорость первого пешехода = х-2=6-2=4 (км/час)

Answer 2

Problem Analysis

We have two pedestrians who start walking towards each other simultaneously and meet after 3 hours. The distance between the two villages is 30 km. We need to find the speed of each pedestrian, given that one pedestrian's speed is 2 km/h less than the other.

Solution

Let's assume the speed of the slower pedestrian is x km/h. Then the speed of the faster pedestrian will be (x + 2) km/h.

We know that the distance traveled by each pedestrian is equal to the product of their speed and time. Since they meet after 3 hours, the distance traveled by the slower pedestrian is 3x km and the distance traveled by the faster pedestrian is 3(x + 2) km.

Since they meet in the middle, the sum of their distances traveled should be equal to the total distance between the villages, which is 30 km.

So, we can set up the following equation:

**3x + 3(x + 2)