Question

Кубик бросили три раза. Найти вероятность выпадения в сумме 12.

Answer 1

Всего исходов 21:(666),(665),(664),(663),(662),(661),(655),(654),(653),(652),(651),(644),(643),(642),(641),(633),(632),(631),(622),(621),(611)
Выпадание в сумме 12 всего 3:(651).(642).(633)
Вероятность равна 3/21=1/7≈0,143

Answer 2

Finding the Probability of Rolling a Sum of 12 with Three Dice

To find the probability of rolling a sum of 12 with three dice, we need to determine the total number of possible outcomes and the number of favorable outcomes.

According to the search results, there are different interpretations of the question. Let's consider two scenarios:

Scenario 1: The question refers to the probability of rolling a sum of 12 on three fair six-sided dice.

In this scenario, each die has six sides numbered from 1 to 6. To find the probability, we need to calculate the number of favorable outcomes (the number of ways to get a sum of 12) and the total number of possible outcomes.

The total number of possible outcomes is given by the formula: total outcomes = number of sides on each die ^ number of dice = 6^3 = 216.

To calculate the number of favorable outcomes, we can use the concept of combinations. We need to find the number of ways to select three numbers from the set {1, 2, 3, 4, 5, 6} such that their sum is 12.

According to the search results, the favorable outcomes are {2, 4, 6}, {3, 3, 6}, and {4, 4, 4}. So, there are three favorable outcomes.

Therefore, the probability of rolling a sum of 12 with three fair six-sided dice is: probability = favorable outcomes / total outcomes = 3 / 216 = 0.0139, or approximately 1.39%.

Scenario 2: The question refers to the probability of rolling a sum of 12 on three dice with an unspecified number of sides.

In this scenario, the number of sides on each die is not specified. Therefore, we cannot provide a specific answer without additional information.

Please let me know if you need further clarification or if there's anything else I can assist you with!