Question

7 (x-5y)+6x=3 (x+4y)+27

Answer 1

7х-35y+6x=3x+12y+27
7x-3x-35y-12y=27
4x-47y=27
-43y=27
y=27:43
y=27\1:43\1
y=27\45

Answer 2

I can help you with your math problem. Here is the detailed solution:

To solve for x and y, we need to simplify the equation and then use substitution or elimination method.

First, we distribute the 7 and the 3 to the terms inside the parentheses:

$$7x - 35y + 6x = 3x + 12y + 27$$

Then, we combine the like terms on both sides of the equation:

$$13x - 35y = 3x + 12y + 27$$

Next, we subtract 3x from both sides and add 35y to both sides:

$$10x = 47y + 27$$

Now, we divide both sides by 10 to isolate x:

$$x = \frac{47y + 27}{10}$$

We can use this value of x to find y by substituting it into the original equation. For simplicity, we will use the equation after distributing the 7 and the 3:

$$7x - 35y + 6x = 3x + 12y + 27$$

Substituting x with $\frac{47y + 27}{10}$, we get:

$$7(\frac{47y + 27}{10}) - 35y + 6(\frac{47y + 27}{10}) = 3(\frac{47y + 27}{10}) + 12y + 27$$

Simplifying the fractions, we get:

$$\frac{329y + 189}{10} - 35y + \frac{282y + 162}{10} = \frac{141y + 81}{10} + 12y + 27$$

Multiplying both sides by 10 to clear the denominators, we get:

$$329y + 189 - 350y + 282y + 162 = 141y + 81 + 120y + 270$$

Combining the like terms on both sides, we get:

$$261y + 351 = 381y + 351$$

Subtracting 351 from both sides and subtracting 261y from both sides, we get:

$$0 = 120y$$

Dividing both sides by 120, we get:

$$y = 0$$

Finally, we can plug in y = 0 into the equation for x to get:

$$x = \frac{47y + 27}{10}$$

$$x = \frac{47(0) + 27}{10}$$

$$x = \frac{27}{10}$$

Therefore, the solution is x = $\frac{27}{10}$ and y = 0.Ответь+подробно.+7+(x-5y)+6x=3+(x+4y)+27