Question

Расстояние между двумя пластинами 240 метров они выехали одновременно навстречу друг другу и встретились через 30 секунд Найдите скорость первого велосипедиста если скорость второго 3 метров секунду

Answer 1

240 :30 =8 м/с -общ скорость
8 - 3 =5 м/с -скорость первого

Answer 2

Problem Analysis

We are given that two cyclists start from two different points and travel towards each other. The distance between the two points is 240 meters. They meet after 30 seconds. We need to find the speed of the first cyclist, given that the speed of the second cyclist is 3 meters per second.

Solution

Let's assume the speed of the first cyclist is v1 meters per second. Since the two cyclists are traveling towards each other, their combined speed is the sum of their individual speeds. Therefore, the combined speed is v1 + 3 meters per second.

We can use the formula distance = speed × time to find the distance traveled by each cyclist. The distance traveled by the first cyclist is 240 meters, and the time taken is 30 seconds.

Using the formula, we can write the equation: 240 = (v1 + 3) × 30

Simplifying the equation, we have: 240 = 30v1 + 90

Subtracting 90 from both sides, we get: 150 = 30v1

Dividing both sides by 30, we find: v1 = 5

Therefore, the speed of the first cyclist is 5 meters per second.

Answer

The speed of the first cyclist is 5 meters per second.