Question

Решите систему способом подстановки 4у-3х=5 х+2у=4

Answer 1

{4y-3x=5
{X=4-2y

{4y-3•(4-2y)=5
{X=4-2y

4y-3•(4-2y)=5
4y-12+6y=5
10y=17
y=17:10
y=1,7
Вернёмся к системе
{y=1,7
{X=4-2y

{y=1,7
{X=4-2•1,7

{y=1,7
{X=4-3,4=0,6
Ответ: (0,6;1,7)

Answer 2

To solve the given system of equations using the method of substitution, we will solve one equation for one variable and substitute it into the other equation. Let's solve the system step by step.

The given system of equations is: Equation 1: 4u - 3x = 5 Equation 2: x + 2u = 4

Step 1: Solve Equation 2 for x In Equation 2, we have x + 2u = 4. Let's isolate x by subtracting 2u from both sides of the equation: x = 4 - 2u

Step 2: Substitute the value of x in Equation 1 Now, substitute the value of x from Step 1 into Equation 1: 4u - 3(4 - 2u) = 5

Simplifying the equation: 4u - 12 + 6u = 5 10u - 12 = 5 10u = 5 + 12 10u = 17 u = 17/10

Step 3: Substitute the value of u into Equation 2 to find x Substitute the value of u into Equation 2: x + 2(17/10) = 4

Simplifying the equation: x + 34/10 = 4 x + 34/10 = 40/10 x = 40/10 - 34/10 x = 6/10 x = 3/5

Therefore, the solution to the given system of equations is: x = 3/5 u = 17/10

Please let me know if you need any further assistance!