
Две улитки начали одновременно ползти навстречу друг другу. они встретились через 3 минуты. Одна
улитка ползла со скоростью 3 м/мин. а другая 2 м /мин..сколько метров пути было между улитками др начала движения? решить двумя способами

Ответы на вопрос

1.3*3=9[м] всего первая улитка
2.2*3=6[м] всего 2 улитка
3.9+6=15[м] всего
Ответ:15 метров
2 способ
3*3+2*3=9+6=15



Problem Statement
Две улитки начали одновременно ползти навстречу друг другу. Они встретились через 3 минуты. Одна улитка ползла со скоростью 3 м/мин, а другая 2 м/мин. Сколько метров пути было между улитками до начала движения? Решить двумя способами.Solution 1: Using Relative Speed
To solve this problem, we can consider the relative speed of the two snails. The relative speed is the sum of their individual speeds when they are moving towards each other.Let's denote the distance between the snails as d (in meters). Snail A is moving at a speed of 3 m/min, and Snail B is moving at a speed of 2 m/min. The time it takes for them to meet is 3 minutes.
Using the formula distance = speed × time, we can calculate the distance traveled by each snail: - Snail A: distance = 3 m/min × 3 min = 9 meters - Snail B: distance = 2 m/min × 3 min = 6 meters
Since they meet after 3 minutes, the total distance between them is the sum of the distances traveled by each snail: d = 9 meters + 6 meters = 15 meters.
Therefore, the distance between the snails before they started moving was 15 meters.
Solution 2: Using Time and Speed
Alternatively, we can solve this problem by considering the time it takes for the snails to meet and their speeds.Let's denote the distance between the snails as d (in meters). Snail A is moving at a speed of 3 m/min, and Snail B is moving at a speed of 2 m/min. The time it takes for them to meet is 3 minutes.
Since they are moving towards each other, their combined speed is the sum of their individual speeds: combined speed = 3 m/min + 2 m/min = 5 m/min.
Using the formula distance = speed × time, we can calculate the distance traveled by the combined speed: distance = 5 m/min × 3 min = 15 meters.
Therefore, the distance between the snails before they started moving was 15 meters.
Conclusion
Both methods yield the same result: the distance between the snails before they started moving was 15 meters.Please let me know if you need any further assistance!


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