Question

Спасательный вертолет совершил пролет 2 вылета. В первый раз он летал 2 ч со скоростью 200км/ч. Во время второго вылета вертолет пролетел на 138 км меньше. Сколько километров пролетел вертолет?

Answer 1

2•200=400(км/ч)
400-138=262(км/ч)
Ответ:262 км/ч пролетел вертолёт.

Answer 2

1) 200*2=400(км) - пролетел вертолёт за первый вылет.
2) 400-138=262(км) - пролетел вертолёт за второй вылет.
3) 400+262=662(км) - пролетел вертолёт всего.
Ответ: 662 км

Answer 3

Calculation of the Helicopter's Total Distance Traveled

To calculate the total distance traveled by the helicopter, we need to find the distance traveled during the first flight and the distance traveled during the second flight.

Let's assume that the distance traveled during the first flight is represented by x kilometers.

During the first flight, the helicopter flew for 2 hours at a speed of 200 km/h. Therefore, the distance traveled during the first flight can be calculated using the formula:

Distance = Speed × Time

Substituting the given values, we have:

x = 200 km/h × 2 h = 400 km During the second flight, the helicopter traveled 138 km less than during the first flight. Therefore, the distance traveled during the second flight can be represented as:

x - 138 km

To find the total distance traveled by the helicopter, we need to add the distances traveled during the first and second flights:

Total Distance = Distance of First Flight + Distance of Second Flight

Total Distance = 400 km + (x - 138 km)

Simplifying the equation, we have:

Total Distance = 400 km + x - 138 km

Combining like terms, we get:

Total Distance = x + 262 km

Therefore, the helicopter traveled a total distance of x + 262 km.

To find the exact value of x, we would need additional information.