Question

Имеется 635г 16% раствора уксуса. Нужно получить 5% раствор. Сколько граммов воды нужно долить для этого к уже имеющемуся раствору?

Answer 1

635*0.16=101.6
101.6:0.05-635=1397

Answer 2

Calculating the Amount of Water Needed to Dilute the Vinegar Solution

To calculate the amount of water needed to dilute the 16% vinegar solution to a 5% vinegar solution, we can use the formula for dilution:

C1V1 = C2V2

Where: - C1 = concentration of the initial solution - V1 = volume of the initial solution - C2 = concentration of the final solution - V2 = volume of the final solution

In this case, we have: - C1 = 16% (or 0.16 as a decimal) - V1 = 635g - C2 = 5% (or 0.05 as a decimal) - V2 = volume of the final solution (which includes the added water)

We can rearrange the formula to solve for V2:

V2 = (C1V1) / C2

Let's calculate the amount of water needed using this formula.

V2 = (0.16 * 635g) / 0.05

V2 ≈ 2032g

So, approximately 2032 grams of water need to be added to the 635 grams of 16% vinegar solution to obtain a 5% vinegar solution.

This calculation assumes that the volumes are additive and that the density of the vinegar solution remains constant during the dilution process.

I hope this helps! If you have any further questions, feel free to ask.