Question

Всего 87 шаров белого, голубого и желтого цвета. Белых и голубых было 58, а голубых и желтых 62.Сколько шариков каждого цвета?

Answer 1

1).87-58=29 (ш) желтого цвета; 2). 87-62=25 (ш) белого цвета; 3). 87-29-25=33 (ш) голубого цвета.

Answer 2

Solution:

Let's solve this problem using a system of equations. We'll denote the number of white balls as w, the number of blue balls as b, and the number of yellow balls as y.

We are given the following information: 1. w + b = 58 (Equation 1) 2. b + y = 62 (Equation 2) 3. w + b + y = 87 (Equation 3)

We can solve these equations to find the values of w, b, and y.

Solving the Equations:

From Equation 1, we can express w as w = 58 - b.

Substituting this value of w into Equation 3, we get: (58 - b) + b + y = 87, which simplifies to: 58 + y = 87, and further simplifies to: y = 87 - 58, y = 29.

Now, we can substitute the value of y into Equation 2 to find b: b + 29 = 62, which simplifies to: b = 62 - 29, b = 33.

Finally, we can substitute the value of b into Equation 1 to find w: w + 33 = 58, which simplifies to: w = 58 - 33, w = 25.

Conclusion:

So, there are 25 white balls, 33 blue balls, and 29 yellow balls.