
Трое маляров могут закончить работу за 5 дней. для ускорения работы добавили еще 2 маляров. за
какое время они закончат работу, если все маляры работают с одинаковой производительностью

Ответы на вопрос

х(дней)=5(маляров)
3*х=5*5
3*х=25
х=25 /3
х=24. 1/3



Problem Analysis
We have three painters who can complete a job in 5 days. To speed up the work, two more painters are added. We need to determine how long it will take for all the painters to complete the job if they work at the same productivity level.Solution
Let's assume that the rate at which each painter works is the same. We can calculate the total productivity of the three original painters and the two additional painters, and then determine how long it will take for them to complete the job together.According to the information given, the three original painters can complete the job in 5 days. This means that their combined productivity is equal to the total work divided by the number of days, which is 1/5 of the job per day.
When two more painters are added, the total number of painters becomes five. Since we assume that each painter works at the same productivity level, the combined productivity of all five painters will be 5 times the productivity of one painter.
To find out how long it will take for all five painters to complete the job, we can divide the total work by their combined productivity.
Let's calculate the time it will take for all five painters to complete the job:
Total work = 1 job Combined productivity of all five painters = 5 times the productivity of one painter
Time required = Total work / Combined productivity of all five painters
Calculation
Total work = 1 job Combined productivity of all five painters = 5 times the productivity of one painterTime required = 1 job / (5 times the productivity of one painter)
Answer
The five painters will complete the job in 1/5 of the time it takes for the three original painters to complete the job.Please note that the specific time required to complete the job cannot be determined without knowing the productivity rate of one painter.


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