Question

А) |1-х|=5 Б) |2+х|=3 Помогите, пожалуйста!

Answer 1

|1-х|=5
|Х|=5±1
|х|=4;6
Х=-4;6
Ответ: -4;6

|2+Х|=3
|Х|=3±2
Х=1;-5
Ответ: 1;-5

Answer 2

Problem Statement

You have two equations that you need to solve:

A) |1-x| = 5 B) |2+x| = 3

Let's solve each equation step by step.

Equation A: |1-x| = 5

To solve this equation, we need to consider two cases: when 1-x is positive and when it is negative.

Case 1: 1-x is positive In this case, the equation becomes: 1-x = 5

To isolate x, we can subtract 1 from both sides: -x = 5 - 1 -x = 4

To solve for x, we multiply both sides by -1: x = -4

Case 2: 1-x is negative In this case, the equation becomes: -(1-x) = 5

To isolate x, we can distribute the negative sign: -1 + x = 5

To isolate x, we can add 1 to both sides: x = 5 + 1 x = 6

Therefore, the solutions for equation A are x = -4 and x = 6.

Equation B: |2+x| = 3

To solve this equation, we also need to consider two cases: when 2+x is positive and when it is negative.

Case 1: 2+x is positive In this case, the equation becomes: 2+x = 3

To isolate x, we can subtract 2 from both sides: x = 3 - 2 x = 1

Case 2: 2+x is negative In this case, the equation becomes: -(2+x) = 3

To isolate x, we can distribute the negative sign: -2 - x = 3

To isolate x, we can subtract 2 from both sides: -x = 3 + 2 -x = 5

To solve for x, we multiply both sides by -1: x = -5

Therefore, the solutions for equation B are x = 1 and x = -5.

Summary of Solutions

The solutions for the given equations are as follows: Equation A: x = -4, x = 6 Equation B: x = 1, x = -5

I hope this helps! Let me know if you have any further questions.