
Решите пожалуйста задачу. Для ёлки родители купили 4 синих шарика, красных на 8 шариков больше чем
синих, а жёлтых шариков столько сколько красных и синих вместе. Во сколько раз меньше купили на ёлку синих шариков, чем жёлтых. Решите пожалуйста!

Ответы на вопрос

2)4+12=16(шариков)-жёлтых
3)16:4=4(раза)
Ответ:в 4 раза



Problem Analysis
To solve this problem, we need to determine the number of blue, red, and yellow balls purchased for the Christmas tree. We are given that the parents bought 4 blue balls, the number of red balls is 8 more than the number of blue balls, and the number of yellow balls is equal to the sum of the red and blue balls. We also need to find the ratio of the number of blue balls to the number of yellow balls.Solution
Let's denote the number of blue balls as B, the number of red balls as R, and the number of yellow balls as Y.We are given that: - B = 4 (the parents bought 4 blue balls). - R = B + 8 (the number of red balls is 8 more than the number of blue balls). - Y = R + B (the number of yellow balls is equal to the sum of the red and blue balls).
To find the ratio of the number of blue balls to the number of yellow balls, we can divide the number of blue balls by the number of yellow balls: B / Y.
Let's substitute the values we know into the equations: - B = 4 - R = B + 8 = 4 + 8 = 12 - Y = R + B = 12 + 4 = 16
Now we can calculate the ratio of the number of blue balls to the number of yellow balls: - B / Y = 4 / 16 = 1/4
Therefore, the number of blue balls is 4, the number of red balls is 12, the number of yellow balls is 16, and the ratio of the number of blue balls to the number of yellow balls is 1/4.
Answer
The parents bought 4 blue balls, 12 red balls, and 16 yellow balls for the Christmas tree. The ratio of the number of blue balls to the number of yellow balls is 1/4.

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