Question

Два ученика вышли одновременно из своих домов навстречу друг другу. Первый ученик шёл со скоростью 60 метров в минуту и прошел до встречи 480 метров. Скорость втооого ученика на 10 метров в минуту больше скорости первого. Какое расстояние до встречи прошел второй ученик? КРАТКАЯ ЗАПИСЬ И РЕШЕНИЕ Срочнооо

Answer 1

1)480/60=8мин- шли до встречи
2)60+10=70 м/мин-скорость 2го
3)70*8=560м -прошел до встречи 2й
Ответ: 560 м

Answer 2

Problem Analysis

We have two students who start walking towards each other from their respective homes. The first student walks at a speed of 60 meters per minute and covers a distance of 480 meters before they meet. The second student walks at a speed that is 10 meters per minute faster than the first student. We need to find the distance covered by the second student before they meet.

Solution

Let's assume that the second student covers the distance to the meeting point in time 't' minutes. Since the first student covers a distance of 480 meters in the same time, we can set up the following equation:

Distance covered by the first student = Distance covered by the second student

60t = (60 + 10)t

Simplifying the equation:

60t = 70t

Subtracting 60t from both sides:

10t = 0

Since the equation simplifies to 10t = 0, it means that t = 0. This implies that the second student has not covered any distance before they meet the first student.

Answer

The second student has not covered any distance before they meet the first student.