Question

Резервуар для поливу поля об'ємом 12600л повністю заповнений водою. До нього підведено три труби. Через одну трубу до резервуара вливається 180л за годину, а через дві труби поливають поле-по 120л за годину черезкожну. Скільки часу можна буде поливати поле, якщо всі труби почнуть "працювати" одночасно?

Answer 1

(120+120)-180=60
12600:60=210 часов

Answer 2

Problem Analysis

We have a reservoir with a capacity of 12,600 liters that is completely filled with water. There are three pipes connected to the reservoir. One pipe pours 180 liters per hour into the reservoir, while the other two pipes each pour 120 liters per hour onto the field. We need to determine how long we can water the field if all the pipes start working simultaneously.

Solution

To find the total amount of water poured into the reservoir per hour, we need to sum the flow rates of all three pipes. The first pipe pours 180 liters per hour, while the other two pipes each pour 120 liters per hour. Therefore, the total flow rate into the reservoir per hour is:

180 liters/hour + 120 liters/hour + 120 liters/hour = 420 liters/hour

Now, we can calculate the time it takes to fill the reservoir by dividing the total capacity of the reservoir by the flow rate:

12,600 liters / 420 liters/hour = 30 hours

Therefore, if all three pipes start working simultaneously, we can water the field for 30 hours.

Answer

If all three pipes start working simultaneously, we can water the field for 30 hours.